Ljubomir Brankovic

Croatia

C0019, 15.12.2007.

#4                                  11+14

1. Qd6! [2. Qxe7+ Rxe7 3. Bxe7+ Ke8 4. Sg7#]

1. ... Bxd6 2. Bxd6+ Re7 3. Bxe7+ Ke8 4. Sg7#

1. ... Qxc5 2. Sxd7+ Rxd7 3. Shxf6 [4. Sxd7/Rxg8#]

1. ... Sxc5 2. Qxf6 [3. Qg7#/3. Rxg8+ Kxg8 4. Qg7#]
                     2. ... Se6 3. Qg7+ Sxg7 4. hxg7#
                          2. ... Bxf6 3. Rxg8+ Kxg8 4. Rxe8#

1. ... Sxb8/Sb6/Sde5 2. Qxf6 [3. Qg7#/ 3. Rxg8+ Kxg8 4. Qg7#]